## Posts Tagged ‘**geometry**’

## “Is this point inside this rectangle?” without IF

The class Point is given below. The hasCode() method uses an helper that you can find in guava. The method equals() contains the only if in this post (promised ;)).

public class Point { public final int x; public final int y; public Point(int x, int y) { this.x = x; this.y = y; } @Override public int hashCode() { return Objects.hashCode(x, y); } @Override public boolean equals(Object obj) { if (obj == null || !(obj instanceof Point)) { return false; } Point point = (Point) obj; return x == point.x && y == point.y; } }

Here is the class Rectangle:

public class Rectangle { public final Point start; public final Point end; public Rectangle(Point start, Point end) { this.start = start; this.end = end; } }

I suppose that start.x < end.x and that start.y < end.y

I define the minimum and the maximum of two points as the point which coordinates are respectively the minimum and the maximum of the coordinates of the given points. For example, the minimum of the points (1, 4) and (3, 2) is (1, 2), and the maximum is (3, 4).

public class Points { // it's an utility class private Points() { throw new UnsupportedOperationException(); } public static Point min(Point p1, Point p2) { return new Point(Math.min(p1.x, p2.x), Math.min(p1.y, p2.y)); } public static Point max(Point p1, Point p2) { return new Point(Math.max(p1.x, p2.x), Math.max(p1.y, p2.y)); } }

Now, I give the method Rectangle.contains() that checks if a point is inside a rectangle. The idea is to use the methods min() and max() between the given point and the rectangle edges as filters: if the computed point is different from the given point, then the given point is not in the rectangle.

import static Points.*; public class Rectangle { // see code above... public boolean contains(Point point) { return point.equals(max(start, min(end, point))); } }